Step 1: Understanding the Concept:
Reductive ozonolysis of an alkene cleaves the double bond and adds an oxygen atom to each of the two formerly double-bonded carbons, forming aldehydes or ketones.
Detailed Explanation:
The products are Formaldehyde (\(HCHO\)) and 2-Methylpropanal (\((CH_{3})_{2}CH-CHO\)).
To find the parent alkene, remove the oxygen atoms and join the two carbonyl carbons with a double bond.
Product 1: \(CH_{2}=O\)
Product 2: \(O=CH-CH(CH_{3})_{2}\)
Joining them: \(CH_{2}=CH-CH(CH_{3})_{2}\)
The structure is \(CH_{2}=CH-CH(CH_{3})_{2}\), which is 3-Methylbut-1-ene.
Step 2: Final Answer:
Compound X is 3-Methylbut-1-ene. Option (1) is correct.