Question:hard

Compound X on reaction with O3 followed by \(\frac{Zn}{H_2O}\) gives formaldehyde and 2-methyl propanal as products. The compound X is:

Updated On: May 1, 2026
  • 3 -Methylbut -1-ene
  • 2-Methylbut -1-ene
  • 2-Methylbut - 2-ene
  • Pent - 2- ene
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
Reductive ozonolysis of an alkene cleaves the double bond and adds an oxygen atom to each of the two formerly double-bonded carbons, forming aldehydes or ketones.
Detailed Explanation:
The products are Formaldehyde (\(HCHO\)) and 2-Methylpropanal (\((CH_{3})_{2}CH-CHO\)).
To find the parent alkene, remove the oxygen atoms and join the two carbonyl carbons with a double bond.
Product 1: \(CH_{2}=O\)
Product 2: \(O=CH-CH(CH_{3})_{2}\)
Joining them: \(CH_{2}=CH-CH(CH_{3})_{2}\)
The structure is \(CH_{2}=CH-CH(CH_{3})_{2}\), which is 3-Methylbut-1-ene.
Step 2: Final Answer:
Compound X is 3-Methylbut-1-ene. Option (1) is correct.
Was this answer helpful?
0