Step 1: Check divisibility of each option.
175 = 5 x 35 (not prime). 161 = 7 x 23 (not prime). 129 = 3 x 43 (not prime).
Step 2: Test 101 for primality.
Since sqrt(101) is less than 11, we only need to check divisibility by primes 2, 3, 5, and 7. 101 is not divisible by any of them.
Step 3: Confirm the answer.
101 has no factors other than 1 and itself, confirming it is a prime number. \[ \boxed{101} \]