tan 90°
1
sin 45°
0
\(\frac{1 - tan² 45°}{1 + tan² 45°}\)
\(= \frac{1 - (1)²}{1 + (1)²}\)
\(= \frac{1 - 1}{1 + 1}\)
\(= \frac{0}{2}\)
= 0
Therefore, option (D) is the correct choice.
Evaluate the following.
(i) sin60° cos30° + sin30° cos 60°
(ii) 2tan245° + cos230° - sin260°
(iii) \(\frac{cos 45°}{sec 30°+cosec30°}\)
(iv) \(\frac{sin\ 30°+tan\ 45°cosec\ 60°}{sec\ 30°+cos\ 60°+cot\ 45°}\)
(v) \(\frac{5cos^260°+4sec^230°-tan^245°}{sin^230°+cos^230°}\)