



Option (1): Bridge Balance Condition
To achieve a balanced bridge:
$$ \frac{P}{Q} = \frac{R}{S} $$
Given:
$$ P = 10 \ \Omega $$
$$ Q = 10 \ \Omega $$
$$ R = 15 \ \Omega $$
$$ S = 5 + R_{diode} $$
A diode with dynamic resistance $R_D = 10 \ \Omega$ can conduct. Under this condition, the bridge will be balanced.
The output (Y) of the given logic gate is similar to the output of an/a :

