Question:medium

Choose the correct answer from the options given below.
A. \( \vec{\nabla} \times \vec{B} = \mu_0 \vec{J} \) represents Ampere's circuital law.
B. \( \vec{\nabla} \cdot \vec{B} = 0 \) represents magnetic monopole doesn't exist experimentally.
C. \( \vec{\nabla} \times \vec{E} = 0 \) represents the conservative nature of the electric field.
D. \( \vec{\nabla} \times \vec{A} = 0 \) represents the solenoidal condition for a vector field.

Show Hint

The curl of a magnetic field \( \vec{\nabla} \times \vec{B} \) is proportional to the current density, and the curl of an electric field \( \vec{\nabla} \times \vec{E} \) is zero in static conditions.
Updated On: Feb 18, 2026
  • (A), (B) and (D) only.
  • (A), (B) and (C) only.
  • (A), (B), (C) and (D).
  • (A), (C) and (D) only.
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Term Definitions.
(A) \( \vec{abla} \times \vec{B} = \mu_0 \vec{J} \) is Ampere's law, with \( \mu_0 \) being the permeability of free space and \( \vec{J} \) the current density.
(B) \( \vec{abla} \cdot \vec{B} = 0 \) indicates the absence of magnetic monopoles.
(C) \( \vec{abla} \times \vec{E} = 0 \) reflects the conservative property of the electrostatic field.
(D) \( \vec{abla} \times \vec{A} = 0 \) defines a condition for a solenoidal vector field.

Step 2: Summary.
Statements (A), (B), (C), and (D) are all valid.
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