Question:medium

Choose a possible probability density function from the given functions:

Show Hint

An exponential function profile of the form $f(x) = \lambda e^{-\lambda x}$ for $x \ge 0$ is the standard model for the Exponential Distribution. Recognizing this pattern with $\lambda = 1$ instantly identifies it as a valid normalized probability distribution.
Updated On: Jun 25, 2026
  • $f(x) = \begin{cases} 1, & 0 \le x \le 2 \\ 0, & \text{otherwise} \end{cases}$
  • $f(x) = \begin{cases} e^{-x}, & x \ge 0 \\ 0, & x < 0 \end{cases}$
  • $f(x) = \begin{cases} \frac{6}{5}x(1+x), & x \ge 0 \\ 0, & x < 0 \end{cases}$
  • $f(x) = \begin{cases} x(1-x), & 0 \le x \le 1 \\ 0, & \text{elsewhere} \end{cases}$
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0