Check which of the following are solutions of the equation x – 2y = 4 and which are not:
(i) (0, 2)
(ii) (2, 0)
(iii) (4, 0)
(iv) \((\sqrt 2 , 4 \sqrt2) \)
(v) (1, 1)
We are given the equation: \( x - 2y = 4 \)
Substitute \( x = 0 \) and \( y = 2 \) into the equation:
\[ 0 - 2(2) = 0 - 4 = -4 \neq 4 \]
Hence, \( (0, 2) \) is not a solution.
Substitute \( x = 2 \) and \( y = 0 \) into the equation:
\[ 2 - 2(0) = 2 - 0 = 2 \neq 4 \]
Hence, \( (2, 0) \) is not a solution.
Substitute \( x = 4 \) and \( y = 0 \) into the equation:
\[ 4 - 2(0) = 4 - 0 = 4 \]
Hence, \( (4, 0) \) is a solution.
Substitute \( x = 1 \) and \( y = 2 \) into the equation:
\[ 1 - 2(2) = 1 - 4 = -3 \neq 4 \]
Hence, \( (1, 2) \) is not a solution.
Substitute \( x = 1 \) and \( y = 1 \) into the equation:
\[ 1 - 2(1) = 1 - 2 = -1 \neq 4 \]
Hence, \( (1, 1) \) is not a solution.