For the given Arithmetic Progression (A.P.), the first term \(a = 11\) and the common difference \(d = a_2 − a_1 = 8 − 11 = −3\). Let the nth term of this A.P. be \(−150\). The formula for the nth term of an A.P. is \(a_n = a + (n-1)d\). Substituting the given values, we get \(-150 = 11 + (n-1)(-3)\). Simplifying this equation, we have \(-150 = 11 - 3n + 3\), which further simplifies to \(-164 = -3n\). Solving for n, we find \(n = \frac {164}{3}\). Since n is not an integer, \(−150\) is not a term of this A.P.
Consequently, \(−150\) is not a term of this A.P.