Question:medium

Calculate the total number of tetrahedral and octahedral voids formed in 0.6 mol of a compound if it forms hcp structure.

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Total voids = 3 $\times$ Total particles. Octahedral = 1 particle; Tetrahedral = 2 per particle.
Updated On: May 14, 2026
  • $3.613 \times 10^{24}$
  • $7.226 \times 10^{24}$
  • $1.084 \times 10^{24}$
  • $2.913 \times 10^{24}$
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
In any close-packed lattice structure (like hcp or ccp/fcc), the number of voids generated depends directly and proportionally on the number of constituent particles forming the lattice.
Step 2: Key Formula or Approach:
If the total number of close-packed particles (atoms) is $N$, then by geometric derivation: Number of octahedral voids = $N$ Number of tetrahedral voids = $2N$ Total number of voids = $N + 2N = 3N$
Step 3: Detailed Explanation:
1. Calculate the number of atoms ($N$): Amount of compound given = $0.6 \text{ mol}$ Using Avogadro's number ($N_A \approx 6.022 \times 10^{23} \text{ mol}^{-1}$): \[ N = 0.6 \text{ mol} \times (6.022 \times 10^{23} \text{ atoms/mol}) \] \[ N = 3.6132 \times 10^{23} \text{ atoms} \] 2. Calculate total voids: Total voids = $3 \times N$ \[ \text{Total voids} = 3 \times (3.6132 \times 10^{23}) \] \[ \text{Total voids} = 10.8396 \times 10^{23} \] 3. Format the mathematical answer: Adjusting the decimal to standard scientific notation format: \[ \text{Total voids} = 1.08396 \times 10^{24} \approx 1.084 \times 10^{24} \] Step 4: Final Answer:
The total number of combined voids is $1.084 \times 10^{24}$.
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