Calculate the solubility in \(\text{mol dm}^{-3}\) of sparingly soluble salt BaBr if its solubility product is \(4.9 \times 10^{-13}\) at the same temperature.
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For \(1:1\) sparingly soluble salts:
\[
K_{sp} = s^2
\]
For \(1:2\) salts like \(CaF_2\):
\[
K_{sp} = 4s^3
\]
Always remember to adjust the expression according to ionic stoichiometry.