Question:medium

Calculate the pH of 0.02 M monobasic acid having 2% dissociation.

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Use the shortcut: $\text{pH} = n - \log m$ when $[H^+] = m \times 10^{-n}$ (here $4 \times 10^{-4}$, so pH $= 4 - \log 4$).
Updated On: May 16, 2026
  • 3.4
  • 4.5
  • 5.1
  • 5.8
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The Correct Option is A

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