Question:medium

Calculate the osmotic pressure of \(0.1\,M\) glucose at \(27^\circ C\).

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Osmotic pressure formula: \[ \pi = iCRT \] For non-electrolytes (like glucose), \(i=1\). Always convert temperature to Kelvin.
Updated On: Apr 21, 2026
  • \(1.23\ \text{atm}\)
  • \(2.46\ \text{atm}\)
  • \(4.92\ \text{atm}\)
  • \(0.82\ \text{atm}\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
We need to find the osmotic pressure of a glucose solution using its molarity and temperature.
Step 2: Key Formula or Approach:
Van't Hoff Equation for osmotic pressure:
\[ \pi = iCRT \]
Where \(C\) is molarity, \(R\) is the gas constant, and \(T\) is absolute temperature.
Step 3: Detailed Explanation:
1. Determine \(i\): Glucose is a non-electrolyte, so it does not dissociate. \(i = 1\).
2. Convert Temperature: \(T = 27 + 273 = 300 \text{ K}\).
3. Constants: \(R = 0.0821 \text{ L atm K}^{-1} \text{ mol}^{-1}\).
4. Calculation:
\[ \pi = 1 \times 0.1 \times 0.0821 \times 300 \]
\[ \pi = 0.1 \times 24.63 \]
\[ \pi = 2.463 \text{ atm} \]
Step 4: Final Answer:
The osmotic pressure of the solution is approximately 2.46 atm.
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