Given:
Avogadro’s number, NA = 6.022 × 1023 mol−1
Atomic mass of He = 4 u
Molar mass of He = 4 g mol−1
(i) Number of atoms in 52 moles of Ar
Number of atoms = Moles × Avogadro’s number
= 52 × 6.022 × 1023
= 3.13 × 1025 atoms
(ii) Number of atoms in 52 u of He
Atomic mass of one He atom = 4 u
Number of atoms = Total mass / Mass of one atom
= 52 / 4
= 13 atoms
(iii) Number of atoms in 52 g of He
Number of moles of He = Mass / Molar mass
= 52 / 4 = 13 mol
Number of atoms = 13 × 6.022 × 1023
= 7.83 × 1024 atoms
Final Answers:
(i) 52 moles of Ar = 3.13 × 1025 atoms
(ii) 52 u of He = 13 atoms
(iii) 52 g of He = 7.83 × 1024 atoms
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?