Given:
Avogadro’s number, NA = 6.022 × 1023 mol−1
Atomic mass of He = 4 u
Molar mass of He = 4 g mol−1
(i) Number of atoms in 52 moles of Ar
Number of atoms = Moles × Avogadro’s number
= 52 × 6.022 × 1023
= 3.13 × 1025 atoms
(ii) Number of atoms in 52 u of He
Atomic mass of one He atom = 4 u
Number of atoms = Total mass / Mass of one atom
= 52 / 4
= 13 atoms
(iii) Number of atoms in 52 g of He
Number of moles of He = Mass / Molar mass
= 52 / 4 = 13 mol
Number of atoms = 13 × 6.022 × 1023
= 7.83 × 1024 atoms
Final Answers:
(i) 52 moles of Ar = 3.13 × 1025 atoms
(ii) 52 u of He = 13 atoms
(iii) 52 g of He = 7.83 × 1024 atoms