Step 1: Use the mole route
$100$ molecules is $\frac{100}{6.022\times10^{23}}$ mol. Molar mass of O$_2$ is $32$ g/mol.
\[ m=\frac{100\times32}{6.022\times10^{23}}=5.314\times10^{-21}\text{ g} \]
Step 2: Get the mass in u
One u is $\frac{1}{6.022\times10^{23}}$ g, so $5.314\times10^{-21}$ g is $3200$ u.
Both values match option (A).
Final Answer:
Same result by moles: $3200$ u and $5.314\times10^{-21}$ g. Option (A).
\[ \boxed{\text{(A)}} \]