Question:easy

Calculate the energy associated with an electron in the first orbit of hydrogen atom?

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Use the Bohr energy formula with n = 1 and Z = 1.
Updated On: Nov 12, 2026
  • \(-2.18\times 10^{-18}\ \text{J}\)
  • \(52.9\ \text{J}\)
  • \(-1.09\times 10^{-18}\ \text{J}\)
  • \(2.18\times 10^{-18}\ \text{J}\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Eliminate wrong signs
Energy of a bound electron must be negative, so $+2.18\times 10^{-18}\ \text{J}$ is wrong.

Step 2: Check the magnitude
The value $52.9\ \text{J}$ mixes up with the Bohr radius (52.9 pm), and $-1.09\times 10^{-18}\ \text{J}$ is half of the correct value.

Step 3: Conclusion
The correct value is $-2.18\times 10^{-18}\ \text{J}$.

Final Answer:
The energy is minus 2.18 times 10 to the power minus 18 joule. \[ \boxed{\text{(A) }-2.18\times 10^{-18}\ \text{J}} \]
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