Question

Calculate $E^0_{cell}$ for $Cd(s) | Cd^{++}(1M) | | Ag^{+}(1M) | Ag(s)$. Given $E^0_{Cd} = -0.403 V$; $E^0_{Ag} = 0.799 V$.

• A. 1.202 V
• B. -1.202 V
• C. 0.396 V
• D. -0.396 V

Hint:

In a galvanic (voltaic) cell, the species with the more positive (or less negative) standard reduction potential ($E^0$) acts as the cathode (undergoes reduction), and the species with the more negative (or less positive) $E^0$ acts as the anode (undergoes oxidation). The standard cell potential is calculated as $E^0_{cell} = E^0_{\text{cathode - E^0_{\text{anode$.

Answer 1

The Correct Option is A