Question:medium
\[\begin{array}{|c|c|c|} \hline 15 & 225 & 30 \\ \hline 7 & 70 & 20 \\ \hline 3 & ? & 8 \\ \hline \end{array} \]
\[\begin{array}{|c|c|c|} \hline 15 & 225 & 30 \\ \hline 7 & 70 & 20 \\ \hline 3 & ? & 8 \\ \hline \end{array} \]
Show Hint
When a center number seems tied to the two ends, try operations like product and then divide by a constant—verify across rows before applying to the missing entry.
Updated On: Aug 18, 2026
- 70
- 12
- 16
- 24
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Confirm the relation \(2\times\text{middle}=\text{left}\times\text{right}\) on the first two rows: \(2\times225=450=15\times30\) and \(2\times70=140=7\times20\).
Step 2: Apply it to the third row, where left \(=3\) and right \(=8\): \(3\times8=24\).
Step 3: Divide by \(2\) to isolate the middle value: \(24\div2=12\).
\[ \boxed{12} \]
Step 2: Apply it to the third row, where left \(=3\) and right \(=8\): \(3\times8=24\).
Step 3: Divide by \(2\) to isolate the middle value: \(24\div2=12\).
\[ \boxed{12} \]
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