Why is chlorobenzene resistant to nucleophilic substitution reactions?
Chlorobenzene demonstrates resistance to nucleophilic substitution reactions owing to several factors:
1. Resonance Stabilization:
The lone electron pair on the chlorine atom engages in resonance with the benzene ring's π-electron system, leading to electron density delocalization. This resonance effect fortifies the C-Cl bond, diminishing its susceptibility to nucleophilic attack.
2. Partial Double Bond Character:
Resonance imbues the C-Cl bond in chlorobenzene with partial double bond characteristics. This augmentation in bond strength consequently curtails its reactivity toward nucleophiles.
3. sp² Hybridization of the Carbon Atom:
The carbon atom directly bonded to chlorine in chlorobenzene is sp² hybridized, being part of the aromatic ring. This hybridization renders it more electronegative and less accessible for nucleophilic substitution when contrasted with the sp³ hybridized carbons found in alkyl halides.
4. High Electron Density on the Ring:
The elevated electron density inherent to the benzene ring acts to repel nucleophiles, thereby further impeding the substitution reaction.
5. Stability of the Aromatic System:
Implementing a nucleophilic substitution would necessitate the disruption of the benzene ring's aromaticity, a process that is energetically disfavored. The inherent stability of the aromatic system makes reactions that compromise it less probable.
Conclusion:
The collective influence of resonance stabilization, partial double bond character, sp² hybridization, high electron density, and aromatic stability collectively render chlorobenzene resistant to nucleophilic substitution reactions.

Statement-I: Glucose exists in two anomeric.
Statement-II: In open chain structure at C-3, C-4, C-5, glucose and fructose have identical configuration. 
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