Question

Average molar kinetic energy of \(CO\) and \(N_2\) at same temperature is:

• A. \(KE_1=KE_2\)
• B. \(KE_1>KE_2\)
• C. \(KE_1<KE_2\)
• D. \(\text {Can't say\  anything.\ Both volumes\  are\  not \ given}\).

Answer 1

The Correct Option is A

To solve this question, let's use the concept of kinetic energy in gases. The average molar kinetic energy of a gas is given by the formula:

KE = \frac{3}{2}RT

Where:

• R is the universal gas constant.
• T is the temperature in Kelvin.

This formula indicates that the average kinetic energy of a gas only depends on the temperature and not on the type of gas. Therefore, at a given temperature, the average molar kinetic energy of any gas will be the same.

Given that the temperature is the same for both CO and N_2, the average molar kinetic energy will be the same for both gases, hence:

KE_1 = KE_2

Therefore, the correct answer is \(KE_1=KE_2\). The other options are incorrect because they suggest a difference in kinetic energy that does not occur under equal temperature conditions.