Question:medium

At T(K), $K_p$ value for the reaction, $2\text{AO}_2(\text{g})+\text{O}_2(\text{g}) \rightleftharpoons 2\text{AO}_3(\text{g})$ is $4\times 10^{10}$. What is the $K'_p$ value for $3\text{AO}_2(\text{g})+\frac{3}{2}\text{O}_2(\text{g}) \rightleftharpoons 3\text{AO}_3(\text{g})$ at T(K)?

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For chemical equilibria, remember how the equilibrium constant is affected by algebraic manipulation of the reaction equation: - Reverse the reaction: $K_{rev} = 1/K$. - Multiply by a factor $n$: $K_{new} = K^n$. - Add two reactions: $K_{new} = K_1 K_2$.
Updated On: Mar 30, 2026
  • $16\times 10^{20}$
  • $8\times 10^{20}$
  • $16\times 10^{15}$
  • $8\times 10^{15}$
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The Correct Option is D

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