Question:hard

At any point on the curve \[ by^2=(x+a)^3, \] if the length of the sub-tangent (ST) and the length of the sub-normal (SN) are such that \[ p(\text{SN})=q(\text{ST})^2, \] then \[ \frac{p}{q}= \]

Show Hint

For tangent-normal problems, remember: \[ \text{Sub-tangent}=\frac{y}{dy/dx}, \qquad \text{Sub-normal}=y\frac{dy}{dx}. \] After finding \(dy/dx\), substitute directly into these formulas.
Updated On: Jul 29, 2026
  • \(\dfrac{2b}{9}\)
  • \(\dfrac{8b}{27}\)
  • \(\dfrac{5b}{8}\)
  • \(\dfrac{27}{8b}\)
Show Solution

The Correct Option is B

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