Assume that a 12-bit Hamming codeword consisting of 8-bit data and 4 check bits is $d_8 d_7 d_6 d_5 c_8 d_4 d_3 d_2 c_4 d_1 c_2 c_1$, where the data bits and the check bits are given in the following tables. Which one of the following choices gives the correct values of $x$ and $y$? 
Step 1: Recall the structure of a (12, 8) Hamming code.
In a (12, 8) Hamming code, the parity (check) bits are placed at positions that are powers of two:
1, 2, 4, and 8.
Each check bit enforces even parity over a predefined set of bit positions that include both data bits and other check bits.
Step 2: Determine the value of x.
The unknown bit x appears in the parity equations corresponding to the relevant check bits
that cover position d5.
Substituting the given data-bit values and enforcing the even parity condition, the parity equation is satisfied only when:
x = 0
Step 3: Determine the value of y.
The unknown bit y is involved in the parity check for c8,
which covers positions including d8, d7, d6, and d5.
Using the known bit values along with x = 0, and again applying the even parity rule, the parity condition is satisfied only when:
y = 0
Final Conclusion:
Both parity conditions are satisfied when:
x = 0 and y = 0
The format of the single-precision floating-point representation of a real number as per the IEEE 754 standard is as follows:
\[ \begin{array}{|c|c|c|} \hline \text{sign} & \text{exponent} & \text{mantissa} \\ \hline \end{array}\] Which one of the following choices is correct with respect to the smallest normalized positive number represented using the standard?
If \( x \) and \( y \) are two decimal digits and \( (0.1101)_2 = (0.8xy5)_{10} \), the decimal value of \( x + y \) is \(\underline{\hspace{2cm}}\).