To solve this problem, let's analyze both the assertion (A) and the reason (R) provided.
- Assertion (A): The polynomial \( p(y) = y^2 + 4y + 3 \) has two zeroes.
- A quadratic polynomial is in the form \( ax^2 + bx + c \), where \( a \neq 0 \). In this case, \( a = 1 \), \( b = 4 \), and \( c = 3 \).
- By the Fundamental Theorem of Algebra, a quadratic polynomial can have at most two zeroes.
- The zeroes of the polynomial can be found using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
- Substituting the values, we have \( a = 1 \), \( b = 4 \), and \( c = 3 \): \(x = \frac{-4 \pm \sqrt{4^2 - 4 \times 1 \times 3}}{2 \times 1} = \frac{-4 \pm \sqrt{16 - 12}}{2} = \frac{-4 \pm \sqrt{4}}{2} = \frac{-4 \pm 2}{2}\).
- This results in two solutions: \( x = -1 \) and \( x = -3 \), indicating that the polynomial has exactly two zeroes.
- Reason (R): A quadratic polynomial can have at most two zeroes.
- The statement correctly identifies the nature of a quadratic polynomial, which, due to its degree being 2, can have at most two solutions/zeroes.
Both the assertion and the reason are true, and the reason serves as a correct explanation for the assertion since it explicitly states that the polynomial \( p(y) = y^2 + 4y + 3 \) is quadratic and therefore can have two zeroes.
Correct Answer: Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).