To determine the correct answer, we evaluate both the assertion (A) and the reason (R) given in the question:
- Assertion (A): "The polynomial \(p(y) = y^2 + 4y + 3\) has two zeroes."
- Reason (R): "A quadratic polynomial can have at most two zeroes."
Let's analyze both statements.
Step-by-step Analysis:
- Understanding the Polynomial:
- The polynomial given is \(p(y) = y^2 + 4y + 3\), which is a quadratic polynomial.
- A quadratic polynomial is of the form \(ax^2 + bx + c\), where \(a \neq 0\).
- Number of Zeroes of a Quadratic Polynomial:
- The fundamental theorem of algebra states that a polynomial of degree \(n\) has exactly \(n\) zeroes (considering multiplicity and within the complex number system).
- For a quadratic polynomial (degree 2), it can have at most two zeroes.
- Verifying Assertion (A):
- We can find the zeroes of the polynomial using factoring: \(p(y) = y^2 + 4y + 3\).
- Factoring gives \[p(y) = (y + 3)(y + 1)\].
- Setting each factor to zero gives the zeroes: \(y + 3 = 0\) or \(y + 1 = 0\), hence, \(y = -3\) and \(y = -1\).
- Thus, the assertion that the polynomial has two zeroes is correct.
- Verifying Reason (R):
- The statement that a quadratic polynomial can have at most two zeroes is indeed correct and aligns with the properties of quadratic polynomials.
Conclusion:
Both (A) and (R) are true. Additionally, (R) provides the correct explanation for why the polynomial \(p(y) = y^2 + 4y + 3\) has two zeroes, because quadratic polynomials always have at most two zeroes. Thus, the correct answer is:
Both (A) and (R) are true and (R) is the correct explanation of (A).