Rankine's theory finds the orientation of the failure plane using the Mohr-Coulomb criterion, which gives the same angular relationship, $\left(45^{\circ} + \phi/2\right)$ measured from the plane carrying the major principal stress, whether we are in the active state or the passive state. Only the identity of which stress is major switches between the two cases. Let's check each statement against this.
The trap in this question is remembering that active failure planes look steep and passive ones look flat when both are measured from the horizontal ground surface. That difference is real, but it happens because the major principal plane itself rotates 90 degrees between the active and passive cases, not because the $45^{\circ}+\phi/2$ rule changes.
Let's summarize:
The false statements are (B) and (D).
A smooth vertical retaining wall supporting layered soils is shown in the figure. According to Rankine's earth pressure theory, the lateral active earth pressure acting at the base of the wall is kPa (rounded off to one decimal place).
