Question:easy
As per IS 456:2000, the maximum spacing of vertical stirrups is to be limited to
As per IS 456:2000, the maximum spacing of vertical stirrups is to be limited to
Show Hint
IS 456:2000 recommends
\[
\boxed{
\text{Maximum stirrup spacing}
=
0.75d
\ \text{or}\
300\,\mathrm{mm},
\ \text{whichever is less.}
}
\]
Updated On: Jul 23, 2026
- \(0.50d\) or \(150\,\mathrm{mm}\)
- \(0.30d\) or \(120\,\mathrm{mm}\)
- \(0.60d\) or \(160\,\mathrm{mm}\)
- \(0.75d\) or \(300\,\mathrm{mm}\)
Show Solution
The Correct Option is D
Solution and Explanation
Step 1: Recall why stirrup spacing has a limit at all.
Diagonal shear cracks in a beam typically form at roughly 45 degrees to the beam axis, so stirrups need to be spaced close enough that at least one stirrup crosses every possible crack.
Step 2: Recall the depth based limit from IS 456:2000.
To make sure a stirrup always intercepts a 45 degree crack, the code limits spacing to \[ 0.75d. \]
Step 3: Recall the absolute upper limit.
Along with this, the code also caps the spacing at an absolute value of \[ 300\,\mathrm{mm}, \] and whichever of the two is smaller governs.
\[ \boxed{0.75d\ \text{or}\ 300\,\mathrm{mm}} \]
Diagonal shear cracks in a beam typically form at roughly 45 degrees to the beam axis, so stirrups need to be spaced close enough that at least one stirrup crosses every possible crack.
Step 2: Recall the depth based limit from IS 456:2000.
To make sure a stirrup always intercepts a 45 degree crack, the code limits spacing to \[ 0.75d. \]
Step 3: Recall the absolute upper limit.
Along with this, the code also caps the spacing at an absolute value of \[ 300\,\mathrm{mm}, \] and whichever of the two is smaller governs.
\[ \boxed{0.75d\ \text{or}\ 300\,\mathrm{mm}} \]
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