Question

Arrange the given material mediums in increasing order of speed of light through them. Given Refractive Indices:

• A = 1.50
• B = 1.46
• C = 1.31
• D = 1.77

Hint:

Higher refractive index → Slower light speed.

Answer 1

To Arrange the Given Media in Increasing Order of Speed of Light

Given Refractive Indices:
A = 1.50
B = 1.46
C = 1.31
D = 1.77

Concept Used:
The speed of light in a medium is given by:

v = c / n

Where:
v = speed of light in the medium
c = speed of light in vacuum
n = refractive index

Since v is inversely proportional to n,
Higher refractive index → Lower speed of light
Lower refractive index → Higher speed of light

Step 1: Arrange in Decreasing Order of Refractive Index
D = 1.77
A = 1.50
B = 1.46
C = 1.31

Step 2: Increasing Order of Speed of Light
Since speed is inversely proportional to refractive index:

D < A < B < C

Conclusion:
The increasing order of speed of light through the given media is:

D, A, B, C