Question:medium

Arrange the following number of teams in a sequential order from less to more with respect to allotment of byes in a Knock-out Tournament :(A) 05
(B) 14
(C) 32
(D) 12
(E) 63

Choose the correct answer from the options given below :

Updated On: Jan 16, 2026
  • (C), (E), (B), (A), (D)
  • (E), (C), (B), (D), (A)
  • (C), (A), (D), (B), (E)
  • (E), (B), (C), (A), (D)
Show Solution

The Correct Option is A

Solution and Explanation

To order teams sequentially by byes in a Knock-out Tournament, determine the next power of 2 equal to or exceeding the team count. The byes needed are the difference between this power of 2 and the team count.

Steps:

1. Find the smallest power of 2 that is greater than or equal to the number of teams.

2. Subtract the number of teams from this power of 2 to get the number of byes.

TeamsNext Power of 2Byes
058 (23)3 (8-5)
1416 (24)2 (16-14)
3232 (25)0 (32-32)
1216 (24)4 (16-12)
6364 (26)1 (64-63)

3. Rank teams by byes in ascending order: 32 (0 byes), 63 (1 bye), 14 (2 byes), 05 (3 byes), 12 (4 byes).

The correct sequence based on the number of byes is: (C) 32, (E) 63, (B) 14, (A) 5, (D) 12.

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