Question:medium

Arrange the following gases in increasing order of van der Waals constant 'a'
A. Ar
B. CH4
C. H₂O
D. C6H6
Choose the correct option from the following.

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Van der Waals constant a is proportional to the strength of intermolecular forces. Hy drogen bonding and larger molecular size significantly increase the value of a.

Updated On: Mar 11, 2026
  • A, B, C and D
  • D, C, B and A
  • B, C, D and A
  • C, D, B and A
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The Correct Option is A

Solution and Explanation

To determine the increasing order of the van der Waals constant 'a' for the gases Ar, CH4, H2O, and C6H6, we need to understand the significance of the van der Waals constant 'a'.

The van der Waals constant 'a' is a measure of the magnitude of attractive forces between gas molecules. The higher the value of 'a', the stronger the intermolecular attractions between the molecules of the gas.

Step-by-step reasoning:

  1. Argon (Ar): It is a noble gas with no dipole moment or significant intermolecular forces. As such, it has the lowest 'a' value among the given options.
  2. Methane (CH4): It is a small non-polar molecule with weak Van der Waals forces.
  3. Water (H2O): It is a polar molecule, capable of hydrogen bonding, so it has a relatively higher 'a' value compared to Ar and CH4.
  4. Benzene (C6H6): Being a larger molecule with the ability to have π-π stacking interactions, it has the highest value of 'a'.

Thus, their increasing order of van der Waals constant 'a' is:

A. Ar < B. CH4 < C. H2O < D. C6H6

The correct option is: A, B, C and D

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