Question

Arrange the following carbocations in increasing stability order \[ A.\ \mathrm{CH_3^+} \] \[ B.\ 1^\circ \] \[ C.\ 2^\circ \] \[ D.\ 3^\circ \] Choose the correct answer from the options given below:
• \( \mathrm{B < A < C < D} \)
• \( \mathrm{A < B < C < D} \)
• \( \mathrm{D < C < B < A} \)
• \( \mathrm{C < B < A < D} \)

• A. \( \mathrm{B < A < C < D} \)
• B. \( \mathrm{A < B < C < D} \)
• C. \( \mathrm{D < C < B < A} \)
• D. \( \mathrm{C < B < A < D} \)

Hint:

Carbocation stability order: \[ \mathrm{CH_3^+ < 1^\circ < 2^\circ < 3^\circ} \] Reason:
• \(+I\) effect
• Hyperconjugation More alkyl groups mean greater stabilization.

Answer 1

The Correct Option is B