Question:medium

Arrange the affinity of hemoglobin (Hb) towards \( \mathrm{CO} \), \( \mathrm{CO_2} \), and \( \mathrm{O_2} \) in increasing order.

Show Hint

Remember that carbon monoxide (\( \mathrm{CO} \)) forms a stable complex with hemoglobin, leading to carbon monoxide poisoning. Oxygen therapy is used to displace \( \mathrm{CO} \) from hemoglobin.
Updated On: Jan 13, 2026
  • \( \mathrm{O_2}>\mathrm{CO_2}>\mathrm{CO} \)
  • \( \mathrm{CO_2}>\mathrm{O_2}>\mathrm{CO} \)
  • \( \mathrm{O_2}>\mathrm{CO}>\mathrm{CO_2} \)
  • \( \mathrm{CO}>\mathrm{CO_2}>\mathrm{O_2} \)
Show Solution

The Correct Option is D

Solution and Explanation

Hemoglobin's (Hb) affinity for various gases is dictated by their chemical interactions with the heme group. The affinity order is as follows: Carbon monoxide (\( \mathrm{CO} \)): Hemoglobin exhibits its highest affinity for \( \mathrm{CO} \), approximately 200-300 times greater than for \( \mathrm{O_2} \). This potent binding severely impedes oxygen transport in the presence of \( \mathrm{CO} \). Carbon dioxide (\( \mathrm{CO_2} \)): Hemoglobin binds \( \mathrm{CO_2} \) to form carbaminohemoglobin, but with a significantly lower affinity than for \( \mathrm{CO} \). Oxygen (\( \mathrm{O_2} \)): Hemoglobin's affinity for \( \mathrm{O_2} \) is lower than for both \( \mathrm{CO_2} \) and \( \mathrm{CO} \). Consequently, the affinity order is: \[ \mathrm{CO}>\mathrm{CO_2}>\mathrm{O_2}. \]
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