Question:easy

Area of the region bounded by the lines \(|x|+|y|=1,\ x\geq 0,\ y\geq 0\) is

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For \(x,y\geq 0\) the line is \(x+y=1\). Find the triangle it makes with the axes.
Updated On: Oct 1, 2026
  • 1 square units
  • \(\frac{1}{2}\) square units
  • 2 square units
  • 4 square units
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Reading the region.
In the first quadrant, $|x|=x$ and $|y|=y$. So the boundary is the line $x+y=1$ together with the two coordinate axes.

Step 2: Use the intercept form.
The line can be written as $\frac{x}{1}+\frac{y}{1}=1$. It has x-intercept 1 and y-intercept 1.

Step 3: Use the area of a triangle.
A triangle formed by the axes and a line with intercepts $a$ and $b$ has area $\frac{1}{2}ab$.
\[ \frac{1}{2}\times 1\times 1=\frac{1}{2} \]

Step 4: Cross-check.
The full diamond $|x|+|y|\leq 1$ has diagonals of length 2, so its area is $\frac{1}{2}\times 2\times 2=2$. It has four equal parts, one in each quadrant. So each quadrant part has area $\frac{2}{4}=\frac{1}{2}$.

Final Answer:
Option 2 is correct. \[ \boxed{\frac{1}{2}\ \text{square units}} \]
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