Question

Aqueous solution of which of the following compounds is the best conductor of electric current?

• A. Ammonia, ${NH3}$
• B. Fructose,${ C6H12O}$
• C. Acetic acid, ${C2H4O2}$
• D. Hydrochloric acid, HCl

Answer 1

The Correct Option is D

To determine which aqueous solution is the best conductor of electric current, we need to understand the ability of the compound to dissociate into ions in the solution. Conductivity in solutions is primarily due to the presence of ions. The more the ions, the better the conductivity.

1. Ammonia ${NH3}$ is a weak base and does not completely dissociate in water. It partially ionizes to form ammonium (${NH4^+}$) and hydroxide (${OH^-}$) ions, resulting in moderate conductivity.
2. Fructose ${C6H12O6}$, being a sugar, does not dissociate into ions in solution. It is a non-electrolyte and does not conduct electricity.
3. Acetic acid ${C2H4O2}$ is a weak acid and only partially ionizes in water to form acetate (${CH3COO^-}$) and hydrogen (${H^+}$) ions. This results in poor conductivity compared to strong acids.
4. Hydrochloric acid (HCl) is a strong acid and completely dissociates into hydrogen (${H^+}$) and chloride (${Cl^-}$) ions in water. This complete dissociation results in excellent conductivity.

Thus, among the given compounds, Hydrochloric acid (HCl) is the best conductor of electric current in its aqueous form because it completely dissociates into ions.