Step 1: Understanding the Concept:
In a standard clock, the minute and hour hands coincide exactly 11 times in every 12-hour period (22 times in 24 hours). This is because the overlap between 11:00 and 1:00 happens only once, at 12:00.
Step 2: Key Formula or Approach:
1. Total time elapsed = Final time - Initial time.
2. Total coincidences = (Full 24-hour days \(\times 22\)) + (coincidences in the remaining hours).
Step 3: Detailed Explanation:
Calculate the duration from 10:20 AM, 8th March to 11:15 AM, 11th March:
- From 10:20 AM, 8th March to 10:20 AM, 11th March = 3 full days (72 hours).
Number of coincidences = \( 3 \times 22 = 66 \).
- Remaining interval: 10:20 AM to 11:15 AM on 11th March.
The hands of a clock coincide once approximately every \( 1 \text{ hour } 5 \frac{5}{11} \text{ minutes} \).
Between 10:00 and 11:00, the hands coincide at approx 10:54 AM.
Since 10:54 AM falls between 10:20 AM and 11:15 AM, there is exactly 1 additional coincidence.
Total coincidences = \( 66 + 1 = 67 \).
Step 4: Final Answer:
The hands were over each other 67 times.