



Anisole is an aromatic ether with the chemical formula \( C_6H_5OCH_3 \). When anisole undergoes cleavage with hydroiodic acid (HI), it results in the formation of phenol and iodomethane (methyl iodide). This cleavage occurs because the \(-OCH_3\) group is effectively split by the reaction with HI, following the reaction mechanism of ethers with hydrogen halides.
The mechanism involves the protonation of the ether oxygen, which makes the methyl group a good leaving group in the form of a molecule of methanol. Upon interaction with iodide ions, methanol is converted into iodomethane.
The equation for this reaction is as follows:
\(C_6H_5OCH_3 + HI \rightarrow C_6H_5OH + CH_3I\)
Thus, the products of the reaction are phenol (\( C_6H_5OH \)) and methyl iodide (\( CH_3I \)).
In this question, the correct answer is the image representing phenol and methyl iodide, as follows:
Hence, the correct product of the reaction between anisole and HI is phenol and methyl iodide, matching the first option.