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An organic compound is heated with \(Na_2O_2\) then boiled with \(HNO_3\). The solution is then treated with ammonium molybdate. The yellow precipitate obtained is due to the presence of the element
An organic compound is heated with \(Na_2O_2\) then boiled with \(HNO_3\). The solution is then treated with ammonium molybdate. The yellow precipitate obtained is due to the presence of the element
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Yellow precipitate with ammonium molybdate is the characteristic test for Phosphate ions (\(PO_4^{3-}\)).
Updated On: Apr 29, 2026
- nitrogen
- sulphur
- phosphorus
- carbon
- molybdenum
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The Correct Option is C
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