Question:medium

An organic compound contains carbon = 38.71%, Hydrogen = 9.67% and Oxygen. The empirical formula of the compound would be:

Show Hint

The empirical formula represents the simplest whole-number ratio of atoms in a compound. Use the percentages of elements to calculate their molar ratios.
Updated On: Jan 15, 2026
  • \( CH_3O \)
  • \( CH_4O \)
  • \( CH_2O \)
  • \( CHO \)
Show Solution

The Correct Option is C

Solution and Explanation

To determine the empirical formula, begin by assuming a 100 gm sample, converting percentages directly to grams:
  • Carbon: 38.71 gm
  • Hydrogen: 9.67 gm
  • Oxygen: 100 - 38.71 - 9.67 = 51.62 gm
Next, divide the grams of each element by its atomic mass:
  • Carbon: \( \frac{38.71}{12} = 3.23 \)
  • Hydrogen: \( \frac{9.67}{1} = 9.67 \)
  • Oxygen: \( \frac{51.62}{16} = 3.23 \)
The approximate simplest whole number ratio, 1:2:1, yields the empirical formula \( CH_2O \).
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