Question:medium
An observer, moving in a straight line with velocity \(100\ \text{m s}^{-1}\), passes a stationary observer. If the object emits note of \(400\) Hz while moving, the change in the frequency noticed by the observer as the object passes past him is \((\text{speed of sound in air}=300\ \text{m s}^{-1})\)
An observer, moving in a straight line with velocity \(100\ \text{m s}^{-1}\), passes a stationary observer. If the object emits note of \(400\) Hz while moving, the change in the frequency noticed by the observer as the object passes past him is \((\text{speed of sound in air}=300\ \text{m s}^{-1})\)
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In Doppler effect, the jump in frequency when the source passes the observer can be found by subtracting the receding value from the approaching value.
Updated On: Apr 29, 2026
- \(350\) Hz
- \(300\) Hz
- \(200\) Hz
- \(100\) Hz
- \(150\) Hz
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The Correct Option is B
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