Question:medium

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Updated On: Jan 13, 2026
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Solution and Explanation

Convex mirror focal length, \(f = +15\ cm\). Object distance, \(u = −10\ cm\). Using the mirror formula, \(\frac 1v-\frac 1u=\frac 1f\).

\(\frac 1v=\frac 1f-\frac 1u\)

\(\frac 1v=\frac {1}{15}+\frac {1}{10}\)

\(\frac 1v=\frac {25}{150}\)

\(\frac 1v = \frac 16\)
\(v=6\ cm\). A positive \(v\) indicates the image is formed behind the mirror.

Magnification, \(m=-\frac {\text {Image\ distance}}{\text {Object\ distance}}\) or \(m =-\frac vu\).

\(m=-\frac {6}{-10}\)

\(m =+0.6\)

A positive magnification indicates a virtual and erect image.

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