An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

Question

Two electrons are moving in orbits of two hydrogen like atoms with speeds $3\times10^{5}\,\text{m/s}$ and $2.5\times10^{5}\,\text{m/s}$ respectively. If the radii of these orbits are nearly same then the possible order of energy states are ___ respectively.

Answer 1

Given:

Mass number, A = 56
Positive charge on ion = +3
Number of neutrons = 30.4% more than electrons

Step 1: Define variables

Let number of electrons = e
Then number of protons = e + 3

Number of neutrons = e + 30.4% of e

Number of neutrons = 1.304 e

Step 2: Use mass number relation

Mass number = Protons + Neutrons

56 = (e + 3) + 1.304e

56 = 2.304e + 3

2.304e = 53

e = 23

Step 3: Calculate protons and neutrons

Number of protons = e + 3 = 23 + 3 = 26

Number of neutrons = 56 − 26 = 30

Step 4: Identify the element

Atomic number = 26

Element with atomic number 26 is Iron (Fe)

Final Answer:

The symbol of the ion is:

⁵⁶₂₆Fe³⁺

An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

Solution and Explanation

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