Question

An ideal gas heat engine operates in a Carnot cycle between \(227^\circ\text{C}\) and \(127^\circ\text{C}\). It absorbs \(6 \times 10^4 \text{ cal}\) of heat at the higher temperature. The amount of heat converted into work is:

• A. \(1.2 \times 10^4 \text{ cal}\)
• B. \(4.8 \times 10^4 \text{ cal}\)
• C. \(2.4 \times 10^4 \text{ cal}\)
• D. \(6.0 \times 10^3 \text{ cal}\)

Hint:

Always convert Celsius to Kelvin first! Skipping temperature conversions is the most common pitfall in thermodynamics problems. Notice that if you incorrectly used Celsius parameters directly (\(1 - \frac{127}{227}\)), you would end up with an unresolvable fraction that does not match any clean test answer choice.

Answer 1

The Correct Option is A