Alternate method: reduced sample space.
Since event B has occurred, restrict attention to the reduced sample space $B = \{1, 3\}$, equally likely given that B occurred.
$1$ is not prime, $3$ is prime. Out of 2 equally likely outcomes, exactly 1 satisfies A.
\[ P(A|B) = \frac{1}{2} = 0.5 \]
This confirms $P(A|B)=0.5$.