Question

An electron is confined to move in a one-dimensional box of length 1˚ A. Its energy in the first excited state is approximately

• A. 150.4 eV
• B. 112.8 eV
• C. 37.6 eV
• D. 342.0 eV

Hint:

Energy in a box increases with n 2 and depends on the size of the box.

Answer 1

The Correct Option is A

The energy of an electron in the first excited state (\( n = 2 \)) within a 1D box of length \( L = 1 \, \text{Å} \) is calculated using the particle-in-a-box model. The quantized energy levels are defined by: \[ E_n = \frac{n^2 h^2}{8mL^2} \] where:

• \( E_n \): electron energy at level \( n \)
• \( n \): principal quantum number (\( n = 2 \) for the first excited state)
• \( h \): Planck's constant (\( 6.626 \times 10^{-34} \, \text{J·s} \))
• \( m \): electron mass (\( 9.109 \times 10^{-31} \, \text{kg} \))
• \( L \): box length (\( 1 \, \text{Å} = 1 \times 10^{-10} \, \text{m} \))

1. Substitute values:
   \[ E_2 = \frac{(2)^2 \times (6.626 \times 10^{-34} \, \text{J·s})^2}{8 \times (9.109 \times 10^{-31} \, \text{kg}) \times (1 \times 10^{-10} \, \text{m})^2} \]
2. Calculate the numerator:
   \[ (2)^2 = 4 \] \[ (6.626 \times 10^{-34})^2 = 4.392 \times 10^{-67} \, \text{J}^2 \cdot \text{s}^2 \] \[ \text{Numerator} = 4 \times 4.392 \times 10^{-67} = 1.757 \times 10^{-66} \, \text{J}^2 \cdot \text{s}^2 \]
3. Calculate the denominator:
   \[ 8 \times 9.109 \times 10^{-31} \times (1 \times 10^{-10})^2 = 8 \times 9.109 \times 10^{-31} \times 1 \times 10^{-20} \] \[ = 7.287 \times 10^{-50} \, \text{kg·m}^2 \]
4. Calculate \( E_2 \):
   \[ E_2 = \frac{1.757 \times 10^{-66}}{7.287 \times 10^{-50}} = 2.414 \times 10^{-17} \, \text{J} \]
5. Convert to electron volts:
   \[ E_2 = \frac{2.414 \times 10^{-17} \, \text{J}}{1.602 \times 10^{-19} \, \text{J/eV}} \approx 150.6 \, \text{eV} \]
6. Round to significant figures:
   \[ E_2 \approx 150.4 \, \text{eV} \]

The energy of the electron in the first excited state is approximately 150.4 eV.