Question:medium

An electromagnetic radiation of wavelength 331.5 nm is made to strike the surface of a metal. Electrons are emitted with a kinetic energy of \(1.2 \times 10^5\) J mol\(^{-1}\). The work function (in eV) of the metal is (h=\(6.63 \times 10^{-34}\) Js, \(N_A = 6 \times 10^{23}\) mol\(^{-1}\))

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The photoelectric effect equation applies to a single photon interacting with a single electron. If any energy is given per mole, you must divide by Avogadro's number to get the per-particle energy before using the equation. A useful shortcut for photon energy is \(E(\text{eV}) = \frac{1240}{\lambda(\text{nm})}\). Here, \(E = 1240/331.5 \approx 3.74\) eV.

Updated On: Mar 30, 2026

1.5
3.0
3.5
2.5

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The Correct Option is D

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