Question:medium

An eigenvector of the matrix
\[ A= \begin{bmatrix} 3 & 2 \\ 1 & 2 \end{bmatrix} \]
is

Show Hint

To verify an eigenvector, simply check \[ \boxed{ AX=\lambda X. } \] If the resulting vector is a scalar multiple of the original vector, then it is an eigenvector.
Updated On: Jul 14, 2026
  • \( \begin{bmatrix} 7\\ 2 \end{bmatrix} \)
  • \( \begin{bmatrix} -2\\ 1 \end{bmatrix} \)
  • \( \begin{bmatrix} -1\\ 2 \end{bmatrix} \)
  • \( \begin{bmatrix} 5\\ -5 \end{bmatrix} \)
Show Solution

The Correct Option is D

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