Question:medium

An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of the escape velocity from the earth. The height \(h\) of the satellite above the earth’s surface is (Take radius of earth as \(R_e\)):

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For circular orbits, remember: \[ v_{\text{orbital}} = \sqrt{\frac{GM}{r}}, \quad v_{\text{escape}} = \sqrt{\frac{2GM}{R}} \] Always distinguish between orbital radius and height above the surface.
Updated On: Mar 23, 2026
  • \(h = R_e^2\)
  • \(h = R_e\)
  • \(h = 2R_e\)
  • \(h = 4R_e\)
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The Correct Option is B

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