During the electrolysis of aqueous CuSO4, copper metal plates the cathode. This occurs as copper ions (Cu\(^{2+}\)) undergo reduction to copper metal (Cu) at the cathode. The cathodic half-reaction is: \[ Cu^{2+} + 2e^- \rightarrow Cu \] While oxygen gas is produced at the anode, the question specifically concerns the cathode, where copper deposition takes place. Therefore, option (A) is the correct choice.