Question

An AND gate is followed by a NOT gate in series. With two inputs ' \(A\) ' and ' \(B\) ', the Boolean expression for the output ' \(Y\) ' will be

• A. \(\overline{A + B}\)
• B. \(\overline{A \cdot B}\)
• C. \(A \cdot B\)
• D. \(A + B\)

Hint:

An AND gate followed by a NOT gate is equivalent to a single NAND gate.

Answer 1

The Correct Option is B