An alkene X ($C_5H_{10}$) on ozonolysis gave formaldehyde and butyraldehyde. The products from the reaction of X with (i) $H_2O/H^{\oplus}$ and (ii) $HBr((C_6H_5COO)_2$ are respectively
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{Markovnikov:} H adds to C with more H (Rich get richer).
{Anti-Markovnikov (Peroxide Effect):} Only with HBr. H adds to C with fewer H.
