Question:medium

An a.c. source is applied to a series LR circuit with $\text{X}_{\text{L}} = 3\text{R}$ and power factor is $\text{X}_1$. Now a capacitor with $\text{X}_{\text{c}} = \text{R}$ is added in series to LR circuit and the power factor is $\text{X}_2$. The ratio $\text{X}_1$ to $\text{X}_2$ is

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Power factor increases as reactance decreases (moving closer to resonance).
Updated On: May 12, 2026
  • $1 : 2$
  • $2 : 1$
  • $1 : \sqrt{2}$
  • $\sqrt{2} : 1$
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The Correct Option is C

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